(2x^2-5x+7)-(4x-3x^2+2)=0

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Solution for (2x^2-5x+7)-(4x-3x^2+2)=0 equation: 



(2x^2-5x+7)-(4x-3x^2+2)=0

We get rid of parentheses

3x^2+2x^2-4x-5x-2+7=0

We add all the numbers together, and all the variables

5x^2-9x+5=0

a = 5; b = -9; c = +5;
Δ = b2-4ac
Δ = -92-4·5·5
Δ = -19
Delta is less than zero, so there is no solution for the equation

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